Solve the Mystery of Four Numbers with Unusual Sums | Homework Help

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The problem involves four numbers A, B, C, and D, with their sums when adding three of the four equaling 20, 22, 24, and 27. The equations derived from these sums are A + B + C = 20, A + C + D = 22, A + B + D = 24, and B + C + D = 27. To solve for the unknowns, one can express A in terms of B and C from the first equation and substitute it into the other equations, reducing the system from four equations to three. This method allows for systematic solving of the values for A, B, C, and D. The discussion emphasizes that introducing an additional variable is unnecessary for solving the equations.
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Okay so there are four numbers represented by A,B,C,D. Their sums when adding three of the four equal the following sums.. 20,22,24, and 27. This is what I have discovered so far but am really stuck.

a+b+c+d=x 20= b+c+d or 20= x-a 22=x-b 24= x-c 27=x-d

Thanks in advance to anyone who can solve this, I really appreciate it!
 
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First, you should be aware that there is a homework forum and I am going to move this thread there.

Second, the 4 3-member subsets of {A, B, C, D} are {A, B, C}, {A, C, D}, {A, B, D}, and {B, C, D}. You have 4 equations: A+ B+ C= 20, A+ C+ D= 22, A+ B+ D= 24, and B+ C+ D= 27. You should be able to solve 4 equations for the 4 unknown numbers. There is no need to introduce a fifth, "x".
Those should be easy to solve. For example, from the first equation, A= 20- B- C. Replace A in the other 3 equations and you have reduced form 4 to 3 equations. Keep doing that.
 
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