Solve the Stone Drop Problem: Acceleration of 9.8m/s^2

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To solve the problem of how long it takes for Carol to hear the stone hit the bottom of a 122.5 m deep mine shaft, the solution involves two parts. First, calculate t1, the time it takes for the stone to fall using the formula for free fall under gravity (9.8 m/s²). Next, determine t2, the time it takes for the sound to travel back up the shaft. The total time Carol waits to hear the sound is the sum of t1 and t2. This method effectively breaks down the problem into manageable calculations.
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i need help on the following problem:
"carol drops a stone into a mine shaft 122.5 m deep. How soon after she drops the stone does she hear it hit the bottom of the shaft?"
i know that the acceleration is 9.8m/s^2 but i can't use it as speed in the speed=distance/time equation
please help me. thanx
 
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Break the problem into two parts.

Calculate t1, the time it takes the stone to fall from her hand to the bottom of the well.

Then find t2, the time it takes the sound to travel from the bottom of the well to the top.

The total time is just t1 + t2.
 

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