Solve Thermo Probs: Part A of PV=mRT w/ Figure

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The discussion focuses on solving part A of a thermodynamics problem using the Ideal Gas Law, PV = mRT. The user calculated the volume of state 2 as half of state 1, determining V1 to be 4.11 cubic meters and V2 as 2.06 cubic meters. To find the temperature, the user needed to establish the pressure, initially questioning how to derive it. They concluded that the pressure remains constant between states 1 and 2 due to the weight of the piston and atmospheric pressure, which do not change. The thread emphasizes understanding the relationship between the piston properties and pressure in thermodynamic calculations.
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Homework Statement


[PLAIN]http://img821.imageshack.us/img821/8541/cheme.png

I am only looking for help in part a.

Homework Equations



PV = mRT


The Attempt at a Solution



By looking at the figure, I was able to calculate the volume of state 2, which is half of the volume of state 1.

V1 = (mRT1)/P1
V1 = (5*0.287*573)/200
V1 = 4.11 meters cubed

V2 = V1/2
V2 = 2.06 meters cubed

However, in order to calculate the temperature by using the Ideal Gas Law, I need pressure first. How do I go about finding pressure? Is there an assumption I'm supposed to make first?
 
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How does the pressure arise initially? Can you connect a property of the piston to the pressure?
 
Mapes said:
How does the pressure arise initially? Can you connect a property of the piston to the pressure?

Well, I guess that since the piston does not exert a force on the air, the pressure stays the same throughout state 1 and 2?

Edit: Actually, the pressure arises from the weight of the piston and the atmospheric pressure. So since those two factors stay the same, the pressure is constant throughout states 1 and 2?
 
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The piston doesn't exert a force on the air? Or the piston exerts a constant force regardless of its height?
 
Mapes said:
The piston doesn't exert a force on the air? Or the piston exerts a constant force regardless of its height?

Yeah I edited my post, because I realized that since the atmospheric pressure and the weight of the piston are constant, the pressure doesn't change from state 1 to state 2. Thanks for the help.
 
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