Solve Time for Tank Filling with 2 Pipes

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A tank can be filled in 6 hours using two pipes, with the larger pipe filling it 5 hours faster than the smaller pipe. The problem involves setting up equations based on their rates, leading to a quadratic equation. The initial attempts at solving resulted in incorrect values for the time taken by each pipe. The correct approach involves using the equation 1/a + 1/(a+5) = 1/6, which simplifies to a quadratic equation a^2 – 7a - 30 = 0. This equation can be solved to find the individual filling times for each pipe.
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Homework Statement



"A tank can be filled in 6 hours using 2 pipes. The larger pipe alone would fill it 5 hours sooner than the smaller pipe alone. How long would each pipe alone take?"

Homework Equations



I know it involves a quadratic not sure on the rest... I can't see how to do with a quadratic i mean.

The Attempt at a Solution


assume a is the big pipe and b is the small
A+B=6
A=B+5 solved them to get a=11/2hours and b=1/2, i can see that's not right. i said that a was the bigger one and my answer says that its not?
 
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pat666 said:

Homework Statement



"A tank can be filled in 6 hours using 2 pipes. The larger pipe alone would fill it 5 hours sooner than the smaller pipe alone. How long would each pipe alone take?"

Homework Equations



I know it involves a quadratic not sure on the rest... I can't see how to do with a quadratic i mean.

The Attempt at a Solution


assume a is the big pipe and b is the small
A+B=6
A=B+5 solved them to get a=11/2hours and b=1/2, i can see that's not right. i said that a was the bigger one and my answer says that its not?


This website may help you

http://www.algebra.com/algebra/home...ems/HOW-TO-Solve-Rate-of-Work-Problems.lesson


So using the the equation form the website you get

1/a + 1/a+5 = 1/6

This simplifies to

(2a+5)/a(a+5) = 1/6

which simplifies down to the quadratic a^2 – 7a -30 = 0
 
ok thanks
 
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