Solve Transmission Lines Homework: Coaxial Cable, 1kOhm, 10Ohm

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A coaxial cable is driven by a pulse source with an internal impedance of 1 kOhm and a load impedance of 10 Ohm, while the characteristic impedance of the cable is 53 Ohm. The voltage at the end of the line needs to be sketched as a function of time for 250 ns, considering the reflection coefficients at both the input and output. The initial voltage division between the source resistance and the cable's characteristic impedance is calculated, leading to a forward traveling wave. The discussion emphasizes understanding how the voltage behaves at the start of the transmission line and what occurs when the wave reaches the load. The key focus is on determining the voltage profile over the specified time duration.
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Homework Statement


can someone help me solving this problem ?
A coaxial cable is driven by a pulse source with internal impedance of
1kohms, 1 V amplitude, square wave with duration of both positive and negative pulse is
800 ns, with negligible rise- and fall-time. The load impedance is 10 ohm.The characteristic ipedance of the coax line is 53 ohms.
Sketch the voltage at the end of the line as function of time for 250 ns.

Homework Equations

The Attempt at a Solution

 
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shivik89 said:
Sketch the voltage at the end of the line as function of time for 250 ns.

nS or uS?

Forum rules require you to at least make an attempt at a solution.
 
CWatters said:
nS or uS?

Forum rules require you to at least make an attempt at a solution.
Thanks for the reply, can you help. it is asked in ns?I tried calculating the reflection coefficent at the input and output but can't get an idea how the voltage will look like
 
Ok what happens at the start of the transmission line - think potential divider.
 
I guess at start.The 1V will be divided between the source resitance of 1 kohms and the characteristic impedance of the cable of 53 ohms. so the forward traveling wave is 53/(1000+53) *1 V ?
 
Yes so a wave/step up of that magnitude sets off down the cable. What happens when it gets to the other end? And what's the voltage that end until it arrives.
 
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