- #1

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0=b(ycos(a)-bcos(2a)+xsin(a))

I've reduced it to

b=ycos(a)+2sin(a)sin(a)+xsin(a)

=sin(a)(cot(a)+2sin(a)+x)

Which I think is right, but I can't get any further without just ending up with different forms that appear more complex.

- Thread starter Islwyn
- Start date

- #1

- 1

- 0

0=b(ycos(a)-bcos(2a)+xsin(a))

I've reduced it to

b=ycos(a)+2sin(a)sin(a)+xsin(a)

=sin(a)(cot(a)+2sin(a)+x)

Which I think is right, but I can't get any further without just ending up with different forms that appear more complex.

- #2

Tom Mattson

Staff Emeritus

Science Advisor

Gold Member

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Try to make use of the following identities:

[tex]\cos(2a)=2\cos^2(a)-1[/tex]

[tex]\sin(a)=\sqrt{1-\cos^2(a)}[/tex]

I don't think you're going to get a closed form expression for a, but if you have numerical values for the parameters you will be able to get approximate solutions.

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