Solve v/(v-1)^2 Integral: Tips & Tricks

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Cannot figure out the integral of : v/(v-1)^2


I tried partial fractions then integrating but didn't get me anywhere! HELP!
 
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Partial fractions should work...why not post what you've got?
 
Try to solve for A and B: v/(v-1)^2 = A/(v-1) + B/(v-1)^2
 
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed
 
elduderino said:
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed

If the original integral is:


\int{\frac{v}{(v-1)^2}}

t=v-1 ; v=t+1

dv=dt

\int{\frac{t+1}{t^2}

Now separate on two fractions and solve two integrals.
 
yeah.. sorry for tht mistake :P
 
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