The probability of achieving 6 in 24 throws of 2 dice is approximately 0.315 or 31.5%. This means that in a large number of trials, we can expect to see a 6 appear in about 31.5% of them.
To calculate the probability, we first need to determine the total number of possible outcomes when throwing 2 dice, which is 36 (6 possible outcomes for the first die, multiplied by 6 possible outcomes for the second die). Out of these 36 outcomes, there are 11 ways to achieve a sum of 6 (1+5, 5+1, 2+4, 4+2, 3+3, 1+5, 5+1, 2+4, 4+2, 3+3, 6+0, 0+6). Therefore, the probability is 11/36, which simplifies to approximately 0.315 or 31.5%.
No, the probability remains the same regardless of the order in which the dice are thrown. In other words, whether the first die shows a 1 and the second die shows a 5, or vice versa, the outcome is still considered a sum of 6 and it is included in the total number of possible outcomes.
The probability could be affected by the type and quality of the dice, the surface on which they are thrown, and the skill or technique of the person throwing them. Additionally, if only a limited number of trials are conducted (less than 24 throws), the actual probability may differ from the expected value.
Yes, this method of calculating probability can be applied to any sum or number that can be achieved by throwing 2 dice. The only difference would be the total number of possible outcomes and the number of ways to achieve the specific sum or number. For example, the probability of achieving a sum of 7 in 24 throws of 2 dice would be 6/36 or approximately 0.167 or 16.7%.