Solved: Wavelength of Scattered Light After Photon-Electron Collision

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The discussion focuses on the scattering of a photon after colliding with an electron, specifically when the photon is scattered backwards along its original path. It suggests that understanding the expected wavelength of the scattered light involves concepts from Compton scattering, particularly for high-energy photons. Participants express uncertainty about the theoretical aspects and the necessity of equations for this scenario. The conversation highlights a need for clarification on the principles behind photon-electron interactions. Overall, the discussion emphasizes the relevance of Compton scattering in determining the wavelength of scattered light.
Allan1993
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Can someone please help me??

A photon collides with an electron and is scattered backwards so that it travels back along its original path. Describe and explain the expected wavelength of the scattered light.

Relevant equations: I'm not sure it's required here, this is more theory rather than calculations



I have no idea what this is on about so i haven't attempted the question. Sorry.
 
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If it's a high energy photon then I recommend looking into Compton scattering.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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