Solved: What Does (i) Mean in 3.86 N(i)?

  • Thread starter Thread starter XwakeriderX
  • Start date Start date
XwakeriderX
Messages
49
Reaction score
0

Homework Statement


Okay, I am just trying to find out what (i) means in this guys work!

Check attachment!

its says somewhere 3.86 N(i) is that initial?
 

Attachments

  • b3d6dc5f-cdd5-49dc-b1a6-54bdc5fc1335.gif
    b3d6dc5f-cdd5-49dc-b1a6-54bdc5fc1335.gif
    13.5 KB · Views: 528
Physics news on Phys.org
Ah okay i think its just a variable to keep track where it came from
 
Nah, he saying i as in \hat{i}[/tex] (there should be a hat on the i...), i.e. the vector component in the i unit vector direction (sometimes also x). It's typical for people to write unit vectors as x->i y->j and z->k.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top