Solving 0.2uf & 0.1uf Capacitance Connected in Series to a 9V Battery

Thread starter ardy121
Start date Nov 21, 2009
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Capacitance

AI Thread Summary

To solve the problem of a 0.2µF and 0.1µF capacitor connected in series to a 9V battery, first, calculate the equivalent capacitance using the formula for capacitors in series, which is 1/C_eq = 1/C1 + 1/C2. The equivalent capacitance is found to be 0.0667µF. Next, determine the charge on each capacitor, which is the same and equal to Q = C_eq * V, resulting in a charge of approximately 0.0006C. Finally, calculate the potential difference across each capacitor using V = Q/C, yielding 4.5V across the 0.2µF capacitor and 4.5V across the 0.1µF capacitor. This approach effectively addresses the problem of capacitors in series connected to a voltage source.

Nov 21, 2009

ardy121

Homework Statement

A 0.2uf and 0.1uf capacitor are connected in series to a 9V battery. Calculate a) the potential difference across each capacitor and b) the charge on each.

Homework Equations

Not sure

The Attempt at a Solution

I don't even know where to begin, sorry :(

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Nov 21, 2009

ardy121

anyone? please help sort of urgent

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