Solving 1D Motion Question with x>0, v<0, a>0

AI Thread Summary
An example of motion where position (x) is greater than zero, velocity (v) is less than zero, and acceleration (a) is greater than zero can be described using the equation x(t) = A + Be^(-γt), with A and B as positive constants. Another example provided is x(t) = 3t^2 - 20t + 100, evaluated at t=2, which satisfies the conditions. At t=1, position is confirmed to be positive, while the velocity is negative and acceleration is positive through calculus differentiation. The discussion emphasizes the importance of using calculus to verify the conditions for motion. Understanding these relationships is crucial for solving similar 1D motion problems effectively.
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Homework Statement


Give example of a motion where x>0, v<0, a>0 at a particular instant.
x-->Position
v-->Velocity
a-->Acceleration


Homework Equations


I thought I had to give an example such as a car, ball etc.
But the answer says:
x(t) ie; position for time t; given by
x(t)=A+Be^{-\gamma t}
where A>B, \gamma>0 are chosen +ve constants.

The Attempt at a Solution


I don't know how to do it. Please help.
 
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the given example wasnt the only solution

another example would be
x(t) = 3t^2 -20t+100 at t=2

for your example use calculus, for at t=1, x>0 as u can check
differentiate dx/dt = -γBe^(-γt), which is less than zero at t=1
differentiating again gives a=(γ^2)(B)(e^-yt) which is positive at t=1
 
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