Solving 2^x=7*5^x: Tips & Tricks

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To solve the equation 2^x = 7 * 5^x, taking the natural logarithm of both sides is essential. The property of logarithms, ln(ab) = ln(a) + ln(b), simplifies the right side to ln(7) + x ln(5). This leads to the equation x ln(2) = ln(7) + x ln(5), which can be rearranged to isolate x. The final solution is x = ln(7) / (ln(2) - ln(5)). This method clarifies the process and helps avoid common mistakes in logarithmic manipulation.
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2^x=7*5^x
I know you have to take ln of both sides but i am having trouble doing that for the right side.
 
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Remember the property of logarithms, ln(ab)=ln(a)+ln(b). That should help you deal with the right hand side.
 
Last edited:
chjopl said:
2^x=7*5^x
I know you have to take ln of both sides but i am having trouble doing that for the right side.

I could give u the only hint possible,but that would be useless.So i'll better show u my version.Logarithmate both sides of the equation to find:
x\ln 2=\ln 7+x\ln 5 =>x=\frac{\ln 7}{\ln 2-\ln 5}.

Okay...??Clear?

PS:Shmoe,u were quicker than me...Again. :-p
 
Yeah thanks a lot i was messing up and having ln7*xln5
 
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