Solving 3z/2=z/6+4: Is it Right?

[thomas576]

3z/2=z/6+4

so

i x multiply and get
18z=2z+8
16z=8

z=1/2

this look right?

thanks

 

[arildno]

Unfortunately no; you forgot to multiply your constant with 6 as well
(with the "constant", I mean the lone "4" in your original equation)

 

[thomas576]

hmm

ok you lost me /shrug

 

[arildno]

3z/2=z/6+4
1. Multiply both sides of the equation with 6:
6*(3z/2)=6*(z/6+4)
OR:
18z/2=6z/6+6*4
Or:
9z=z+24
That is:
8z=24
Whereby:
z=3

Note:
I didn't bother with your cross-multiplication; that was an unnecessary operation.