The second one is a PDF file so you will need Adobe Acrobat Reader to read it.

gimak
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Homework Statement


y=[(1+y^2)^1.5]/[2(y+sqrt 3)^2]; solve for y

Homework Equations


see above

The Attempt at a Solution


I tried to use algebra to solve it, but I can't. The textbook says it can be solved numerically or by iteration. By numberically I think it means algebraically. But I don't know how to do it that way. I don't know what it means by iteration. Can you guys give me an idea of how to do it both ways?
 
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Numerically means using a computer or graphing method to find the answer. Bring the y to the right side so you have f(y)=0. Then plot it to see where f(y) crosses the axis.
Iteration to me also implies a numerical solving method that starts with a guess and moves closer to the zero until you are as close as you need to be.
 
Take the denominator to L.H.S and square both sides. Can you see a pattern?
 
gimak said:

Homework Statement


y=[(1+y^2)^1.5]/[2(y+sqrt 3)^2]; solve for y

Homework Equations


see above

The Attempt at a Solution


I tried to use algebra to solve it, but I can't. The textbook says it can be solved numerically or by iteration. By numberically I think it means algebraically. But I don't know how to do it that way. I don't know what it means by iteration. Can you guys give me an idea of how to do it both ways?

Numerically is NOT algebraically. Rather than trying to explain it I will just give a link to explanations that others have already written out. See
http://mathforum.org/library/drmath/view/61677.html or
http://cfd.mace.manchester.ac.uk/twiki/pub/Main/TimCraftNotes_All_Access/cfd1-numanal.pdf
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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