doroulla
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the question is to solve:
dx/dt -2t(2x-1)=0
when t=0, x=0..
I integrated and found:
ln(2x-1)=2t^2 + k
then : 2x-1 = e^2t^2 -2
then i put in the x=0 when t=0 and i found that k=-2
the solution i found is:
x= 0.5e(2t^2) - 0.5
is this correct? Thank you very much
dx/dt -2t(2x-1)=0
when t=0, x=0..
I integrated and found:
ln(2x-1)=2t^2 + k
then : 2x-1 = e^2t^2 -2
then i put in the x=0 when t=0 and i found that k=-2
the solution i found is:
x= 0.5e(2t^2) - 0.5
is this correct? Thank you very much