Solving a Differential Equation with Integrating Factors

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Homework Help Overview

The discussion revolves around solving a differential equation of the form (x+1)y' + 2y - (x+1)^(5/2) = 0, which falls under the subject area of differential equations, specifically first-order linear equations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to manipulate the equation to isolate x and y but encounters difficulties. Some participants suggest specific forms for particular solutions and mention the need to solve the homogeneous equation. Others inquire about integrating factors and express uncertainty regarding their understanding of the topic.

Discussion Status

The discussion is ongoing, with participants exploring various approaches to the problem. Some guidance has been offered regarding particular solutions and the homogeneous equation, while others are questioning foundational concepts like integrating factors.

Contextual Notes

Participants note varying levels of familiarity with first-order linear differential equations and express concerns about the complexity of the problem. There is a mention of imposed homework rules regarding the methods learned so far.

CalculusHelp1
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Homework Statement



Find the solution to (x+1)y' +2y -(x+1)^(5/2)=0

Homework Equations



definition of antiderivative


The Attempt at a Solution



I have been trying to manipulate this equation in every possible way so that I can get x on one side and y on the other. Ever attempt has led to a dead end. I tried to factor the (x+1) terms, tried to carry things over to the other side, nothing is working.

Can anyone give me a nod in the right direction so I can tackle this problem? Thanks
 
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For a particular solution, you might try

[tex]y_p = a (x+1)^b,[/tex]

where there's an obvious guess for [tex]b[/tex] if you think a bit before doing any calculations. Otherwise, plug this in and see what values of [tex]b[/tex] and [tex]a[/tex] solve the equation.

To get the full solution, you also have to solve the homogeneous equation

[tex](x+1)y' +2y =0[/tex]

which will give you a function [tex]y_h(x)[/tex]. The general solution to the original equation is [tex]y=y_h + y_p[/tex].
 
Multiply by (x+1), then notice that:

[tex]\frac{d}{dx}\left((x+1)^2y\right)=(x+1)^2y'+2(x+1)y[/tex]
 
Okay this problem might be over my head. I've only just learned first order linear differential equations and solving them by separation of variables.

Is there any easier way to do this?
 
CalculusHelp1 said:
Okay this problem might be over my head. I've only just learned first order linear differential equations and solving them by separation of variables.

Is there any easier way to do this?

Have you learned about integrating factors?
 
No, what are those?
 
CalculusHelp1 said:
No, what are those?

I could give a reasonably good answer, but Paul of Paul's Online Math Notes does a better job. Just Google : "integrating factors, pauls online math notes"
 

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