Solving a differential equation

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Homework Statement


Solve
(1+bx)y''(x)-ay(x)=0

Homework Equations


The Attempt at a Solution



I'm used to solving homogeneous linear ODE's where you form a characteristic equation and solve that way, here there is the function of x (1+bx) so how does that change things?
 
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Would dividing both sides by 1+bx help?
 
Ok so if I did that then what? I can define a characteristic equation such that

r^2-\frac{a}{1+bx}=0

and r=\pm\sqrt{\frac{a}{1+bx}}

where b^2-4ac = 4a(1+bx) > 0

so a solution is y=ce^{rx} but that doesn't satisfy the ODE so its not correct?
 
You can't use constant coefficient methods on a DE like this with variable coefficients. Perhaps there is a clever substitution that will help, or maybe not. Problems like this are typically solved with series solutions, especially if you know ##a## and ##b##. Where did this equation come from? If it's from a text, the recent material may give a hint how to solve it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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