Solving a Directional Speed Problem: Need Help!

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To solve the directional speed problem, doubling the speeds of 4.8 mph South and 3.6 mph East results in 9.6 mph South and 7.2 mph East. The combined velocity should be expressed in terms of both speed and direction. The discussion confirms that multiplying each vector by 2 is correct. Therefore, the final answer is 9.6 mph South and 7.2 mph East. Understanding vector components is essential for accurately combining speeds in different directions.
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Homework Statement


A person is traveling (4.8 mph and 3.6 mph) in a South and East direction. If the person doubles speed in same directions what is the answer.. I have no idea how to solve this problem. Can i just multiply both vectors by 2

Homework Equations





The Attempt at a Solution


4.8 x 2 = 9.6 mph
3.6 x 2 = 7.2mph

Would the Soulution be 9.6mph and 7.2 mph .. I don't know Please help
 
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I am not sure what answer they are looking for based on the given problem as you state it, but I would surmise that they want to know the velocity (that is, speed and direction) of the two vectors combined.
 
The answer would be in this format ( X speed in South; X speed in East)
 
Welcome to PF!

Bryanaam said:
A person is traveling (4.8 mph and 3.6 mph) in a South and East direction. If the person doubles speed in same directions what is the answer.. I have no idea how to solve this problem. Can i just multiply both vectors by 2

Hi Bryanaam! Welcome to PF! :smile:

Yes … if a vector is doubled, then its components are doubled.

(This is because vectors are from vector spaces, and every vector space has scalars (ordinary numbers, in this case), and they obey the distributive law, eg 2(A.B) = (2A).B )
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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