Solving a equation of a circle

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To find the center and radius of the circle from the equation x^2 + y^2 + 2√2x - 4√5y = 5, the first step is to rearrange and group the terms. Completing the square for both the x and y variables is essential to transform the equation into the standard form (x-h)^2 + (y-k)^2 = r^2. This involves adjusting the equation to isolate the squared terms and determining the values of h, k, and r. Once completed, the center of the circle can be identified as (h, k) and the radius as r. Properly following these steps will yield the desired results.
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Find the center and radius of the circle using the equation:

x^2 + y^2 + 2√2x - 4√5y = 5

I just can't seem to solve this equation into the form (x-h)^2 + (y-k)^2 = r^2 in order to get the center and radius.

Any help would be appreciated
 
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You would need to show us what you have tried. First thing you do is group up the terms and complete the square.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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