natgbz
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Can't remember how to do this (trying to solve for D):
x = b/D + a*log(D)
Any takers? Or is this impossible?
x = b/D + a*log(D)
Any takers? Or is this impossible?
symbolipoint said:Additive inverse of b/D;
Multiplicative inverse of 'a';
Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?
HallsofIvy said:One doesn't. Not in terms of elementary functions anyway. It might be possible to solve it in terms of the "Lambert W function".