Solving a Maple Mystery: Why Does x=root(x^2+1)/x=.5root(2+root(20))?

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fredrick08
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Homework Statement



can someone please tell me why maple says that x=root(x^2+1)/x=.5root(2+root(20))??

ive tried trig and rearranging, but i have idea why this is so..
 
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Have you got a value stored into the variable x?

EDIT: Oh i think i may have misinterpreted the problem.

Heres some working:
http://img4.imageshack.us/img4/8552/algebra.gif

Probably is a quicker way, but these are the steps i took.
 
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fredrick08 said:

Homework Statement



can someone please tell me why maple says that x=root(x^2+1)/x=.5root(2+root(20))??

ive tried trig and rearranging, but i have idea why this is so..

Square both sides, and you get a quadratic in x2. Solve.

[tex]\begin{align*}<br /> x &= \frac{\sqrt{x^2+1}}{x} \\<br /> \intertext{Hence}<br /> x^2 &= \sqrt{x^2 + 1} \\<br /> x^4 &= x^2 + 1 \\<br /> x^2 &= \frac{1 \pm \sqrt{5}}{2} \\<br /> \intertext{(Must be positive, so dismiss the negative part)}<br /> & = \frac{2 + \sqrt{20}}{4} \\<br /> \intertext{Hence}<br /> x & = \pm 0.5 \sqrt{2 + \sqrt{20}} \\<br /> &= \pm \sqrt{0.5 + \sqrt{1.25}}<br /> \end{align*}[/tex]​
 
thankyou very much, I am still unsure how you get from x^4 to x^2=2+root(20)/4.. but i know its right so thx
 
ok yes thankyou