Solving a Math Problem: Overcoming a Mental Lapse

  • Thread starter Thread starter derekmohammed
  • Start date Start date
AI Thread Summary
The discussion revolves around a user experiencing a mental block while trying to rewrite the formula 3(cos^2(x)sin^2(x)) in terms of the identity sin(2x) = 2sin(x)cos(x). The user seeks assistance in transforming the expression correctly. A helpful note is provided, indicating that cos^2(x)sin^2(x) can be expressed as (cos(x)sin(x))^2, which can be manipulated further. The conversation emphasizes the importance of understanding trigonometric identities for solving such problems. Overall, the thread highlights collaborative problem-solving in mathematics.
derekmohammed
Messages
105
Reaction score
0
Hi

I am having a little bit of a mental lapse right now :cry: :zzz: and I was wondering if someone could help me out.

I want to write the formula as

3(cos^2(x)sin^2(x)) to the identity sin2x = 2sinxcosx

Thanks ALOT!
 
Last edited:
Physics news on Phys.org
Note that:
\cos^{2}x\sin^{2}x=(\cos{x}\sin{x})^{2}=(\frac{2\cos{x}\sin{x}}{2})^{2}
 
Thanks arildno...
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top