Jess89
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Hello, please can someone tell me how to decouple and solve this equation? It was on a problem sheet, but the solution jumped to the decoupled equation... =(
<br /> \frac{dx}{dt} = 2x+y-t<br />
<br /> \frac{dy}{dt}=2x-y+t <br />
I know that it can rewritten as
<br /> <br /> \frac{d}{dt}\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] \left[\begin{array}{cccc} x\\ y \end{array}\right] + \left[ \begin{array}{cccc} -t\\ t \end{array} \right]<br /> <br />
And for that matrix :
<br /> <br /> \left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] <br /> <br />
the eigenvalues and eigenvectors can be worked out.
But I don't know how to decouple =(
Thank you !
<br /> \frac{dx}{dt} = 2x+y-t<br />
<br /> \frac{dy}{dt}=2x-y+t <br />
I know that it can rewritten as
<br /> <br /> \frac{d}{dt}\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] \left[\begin{array}{cccc} x\\ y \end{array}\right] + \left[ \begin{array}{cccc} -t\\ t \end{array} \right]<br /> <br />
And for that matrix :
<br /> <br /> \left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] <br /> <br />
the eigenvalues and eigenvectors can be worked out.
But I don't know how to decouple =(
Thank you !
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