Solving a Parallel-Plate Capacitor Problem

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To solve the parallel-plate capacitor problem, the capacitance can be calculated using the formula C = ε₀(A/d), where ε₀ is the permittivity of free space, A is the area of the plates, and d is the separation distance. The charge on the capacitor can be determined using Q = C * V, where V is the voltage supplied by the battery. The uniform electric field between the plates is found using E = V/d. Participants in the discussion emphasize the importance of showing work to receive guidance, rather than simply asking for answers. Understanding the underlying concepts is crucial for solving the problem effectively.
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need your help!

An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 1.00 mm. The capacitor is connected to a 3.0 V battery.
(a) Find the value of its capacitance.
-------pF

(b) What is the charge on the capacitor?
----- pC

(c) What is the magnitude of the uniform electric field between the plates?
------N/C
 
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What have you done so far? Show us your work and we can point you in the right direction. We aren't going to do this for you. That's not going to help you at all.
 


i don't understand it at all!
 

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