Solving Algebra Homework: 6+X = 3+(X/2)

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The discussion focuses on solving the algebraic equation 6 + X = 3 + (X/2). The user initially misapplies the quadratic formula and misinterprets the right-hand side of the equation. After receiving guidance, they correctly identify the need to multiply both sides by 2 and establish a common denominator. The correct solutions to the equation are X1 = 2 and X2 = -6, demonstrating the importance of accurate operations in algebraic manipulation.

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Homework Statement


6+X = 3+(X/2)
----
X


Homework Equations


Quadratic formula?


The Attempt at a Solution


2(6+X) = 3+X
------
X

12+2X = 3+X
------
X

12+2X = X(3+X)

12+2X = 3X-X^2

so,

X^2+X-12

when putting it in the quadratic formula, I don't get the right answers.
the answer should be X1= 2 X2= -6
what have I done wrong? :(
 
Last edited:
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You're messing up your operations. Go back to the first line in your attempt. The RHS is 3 + x/2 NOT (3 + x)/2

Try again
 
Starting with (X+6)/X=3+X/2, if you multiply both sides by 2 you get (2X+12)/X=6+X. Note the 6 instead of a 3. 3+X/2 is not the same as (3+X)/2.
 
I haven't followed the whole thing through. But it looks like your first move is to multiply both sides by 2 and you got the wrong answer on the right side of the equation.

You wouldn't get 3+X, you'd get 2(3+X/2).

For the first step, you need to make a common denominator (2) on the right side before you multiply both sides by two. Does that make sense?

Or, do it Dick's way.
 
Thank you very much! I got the right answer now. Am I supposed to grade the help I got? If so, how?

I'll probably have some more questions tonight... can I just post it in here or should I create a new thread?
 
Grades? Grade US? We don't need no steenking grades! :) If it's a new question start a new thread, old long threads tend to get overlooked.
 
Oh, thought you were supposed to grade it as in some swedish forums :D.
Well, thank you again!
 
If you want, give out ATTABOYs. When posters get 20 ATTABOYs, it cancels out one MY BAD!
 

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