Solving an Acceleration Problem - Tips & Guidance Needed

  • Thread starter Thread starter shiftless
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
The discussion centers on solving a differential equation to calculate the displacement of a land vehicle over time, considering constant mass, thrust from a jet engine, and atmospheric drag. The equation involves the vehicle's velocity and atmospheric resistance, leading to a first-order non-linear differential equation. Participants suggest separating variables to solve the equation and integrating to find displacement. One user successfully implemented a brute-force solution in C, although they acknowledge that a more elegant mathematical approach exists. The conversation highlights the complexity of the problem and the need for a solid understanding of differential equations.
shiftless
Messages
2
Reaction score
0
Hi folks, I have a problem that I am trying to figure out that I hope you can help me with. I don't want to be spoon fed as I like discovering things for myself, but this one has me stumped and I'd appreciate some guidance.

The end result I am trying to obtain is a function which allows me to calculate the displacement of a land vehicle with respect to time, given its mass (constant, for the purposes of this simplified calculation), thrust from its jet engine (same), no friction, and here is the kicker, atmospheric drag. The problem as I am sure you are well aware is that drag increases as a square of velocity. The velocity function is a derivative of displacement so I am looking at a function which includes its own derivative.

I have studied Calculus I and II in college and I don't believe they alone provide me with the tools I need to solve this problem. It's been a while though so it's possible I've simply forgotten something that could help me. I did some Google searching and it appears that differential equations are what I need to know. However, I don't want to have to go out and buy a book on differential equations and study it for 6 weeks just to solve this one problem; if someone could just give me a somewhat detailed summary of what I'm up against and some tips and ideas on how I should go about tackling it, that would be very helpful.

Thanks in advance!
 
Last edited:
Physics news on Phys.org
Dear friend!
hi
please write the equation which you want to solve. I will help u.

best,
 
Hi Shiftless, welcome to PF. Yes you are looking into solving a differential equation of the form:

x'' = a - b x'^2

This may look fairly simple, but it is actually a pretty advanced equation to solve. I don't even think that an equation of this form would be covered by the first semester of differential equations. You will probably have to look it up in a reference book. The only way I could solve it is with Mathematica.

EDIT: actually, this is the same as the differential equation

v' = a - b v^2

which is a first order non-linear differential equation
 
Last edited:
shiftless said:
The end result I am trying to obtain is a function which allows me to calculate the displacement of a land vehicle with respect to time, given its mass (constant, for the purposes of this simplified calculation), thrust from its jet engine (same), no friction, and here is the kicker, atmospheric drag.

I assume you mean atmospheric resistance instead of atmospheric drag. :smile:

Let's call m the mass of the vehicle, f_j the thrust from its jet engine and f_a=-k\,v^2 the atmospheric resistance where k is a constant and v=\frac{d\,x}{d\,t} the velocity of the vehicle.
From Newton's 2nd law we have

m\,\frac{d\,v}{d\,t}=f_j+f_a\Rightarrow\frac{d\,v}{d\,t}=\frac{f_j}{m}-\frac{k}{m}\,v^2

This is actually the DE DaleSpam, mentioned. This is a fisrt order DE that is separatable (if my English are correct! :smile:). In order to solve it you must do what the name suggests ...separate it! That is to bring all the v dependence is in one side of the equation and the t dependence on the other, i.e.

\frac{d\,v}{\frac{f_j}{m}-\frac{k}{m}\,v^2}=d\,t\Rightarrow\int\frac{d\,v}{\frac{f_j}{m}-\frac{k}{m}\,v^2}=t+\tau \quad (1)

where \tau is the constant of intergration. Having found the function v(t) the only thing you to do in order to find the displacement of the vehicle x(t) is to integrate it once more, i.e.

x(t)=\int v(t)d\,t+x_o

where x_o is a second constant of integration.

P.S.1 If you have trouble with the integration of (1), try to split the fraction into two simpler ones
\frac{1}{\frac{f_j}{m}-\frac{k}{m}\,v^2}=\frac{A}{\sqrt{\frac{f_j}{m}}-\sqrt{\frac{k}{m}}\,v}+\frac{B}{\sqrt{\frac{f_j}{m}}+\sqrt{\frac{k}{m}}\,v}

P.S.2 If you insist on atmospheric drag replace k with -k, in which case you have an integral of the form
\int \frac{d\,z}{a^2+b^2\,z^2}
which is resolved with the help of arc tangent function.
 
Hey, thanks! That's exactly what I was looking for. After posting this thread I went and wrote a simple C program to solve the problem by brute force; i.e. an iterative solver. It works, and it gave me an accurate solution, but not quite as elegant as doing it your way.
 
Thread 'Is 'Velocity of Transport' a Recognized Term in English Mechanics Literature?'
Here are two fragments from Banach's monograph in Mechanics I have never seen the term <<velocity of transport>> in English texts. Actually I have never seen this term being named somehow in English. This term has a name in Russian books. I looked through the original Banach's text in Polish and there is a Polish name for this term. It is a little bit surprising that the Polish name differs from the Russian one and also differs from this English translation. My question is: Is there...
I know that mass does not affect the acceleration in a simple pendulum undergoing SHM, but how does the mass on the spring that makes up the elastic pendulum affect its acceleration? Certainly, there must be a change due to the displacement from equilibrium caused by each differing mass? I am talking about finding the acceleration at a specific time on each trial with different masses and comparing them. How would they compare and why?
Back
Top