Solving Angular Momentum & Energy Conservation for Velocity at Point A

AI Thread Summary
The discussion revolves around a problem involving a disk connected to a spring and a mass m that collides with it. The main focus is on applying the conservation of angular momentum to determine the initial angular velocity (ω) after the mass sticks to the disk. Participants express uncertainty regarding the gravitational potential energy in the energy conservation equation and the diagram's interpretation. There is confusion about whether the disk is resting on the floor or pivoted at its center, affecting the velocity components. Clarifications about the disk's position and mass are sought to resolve the problem effectively.
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Homework Statement



Hey guys.
So I got this disk connected to a spring which is connected to a wall.
A mass m hits the disk with a velocity v and sticks to it.
The question is to find the velocity of m at point A.
As you can see I used the conservation of the angular momentum to find \omega at the beginning.
The thing I'm not sure about is the energy conservation equation I wrote there, I'm not sure about the gravitational potential energy, I mean, is this right?

10x.

Homework Equations





The Attempt at a Solution

 

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Any idea guys?
 
asi123 said:
Any idea guys?

I'm not sure I fully understand the diagram, but shouldn't v*cos(squiggle)=0?
 
OmCheeto said:
I'm not sure I fully understand the diagram, but shouldn't v*cos(squiggle)=0?

Why?
 
asi123 said:
Why?
That's why I posted that I didn't understand the diagram.
Is the disk resting on the floor at y=0?
Is the disk pivoted frictionlessly at it's center?

I assumed that since you mentioned gravity, that the disk is in a vertical plane.

My assumption was that the disc was fixed on some axis or point and therefore the v*cos(squiggle) component had to be zero. Also, none of the momentum of the mass m would be imparted to the disc as there was no mention of it's mass. So the magnitude of of the velocity of mass m would have to be the same in the direction of sin(squiggle).

Hope that helps.
 
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