Solving Archimedes Principle: 6500kg Iceberg in Sea

AI Thread Summary
To solve the problem of a 6500kg iceberg in the sea, the buoyant force can be determined using the equilibrium of forces, where the weight of the iceberg equals the buoyant force. The volume of water displaced can be calculated from the density of seawater and the buoyant force. The fraction of the iceberg's volume below the waterline can then be derived from the volume of water displaced relative to the iceberg's total volume. The discussion highlights the importance of understanding the principles of buoyancy and equilibrium in fluid mechanics. The problem was resolved with guidance from the forum, emphasizing collaborative learning.
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Homework Statement


a 6500kg iceberg is afloat in the sea. the icebergs density is 930kg/m^3 and the sea water has density of 1030kg/m^3
a) find the buoyant force on the iceberg
the volume of water displaced and the fraction of the icebergs volume that is below the waterline.


Homework Equations



F_B=x_displaced=rho g V

The Attempt at a Solution


i have no idea how to do this i thought that maybe since its not sinking its in equilibrium relative to something but i have no idea if that's even right or not.. thanks for any help in advance.
 
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You are on the right track. It is pulled down by gravity, and pushed up by buoyancy - these are two forces in equilibrium. One of these is very easy to calculate from the data given - that gives you the other one (they are in equilibrium, which means they are identical).
 
ok thank you i can't believe i missed that - problem solved thanks to you and PF!
 
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