Solving Atwood's Machine: Find Accel & Time for 60 cm

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The discussion focuses on solving an Atwood's Machine problem involving a pulley with specific mass and radius, and two hanging weights of 1.1 kg and 1.05 kg. The user successfully calculated the acceleration but seeks assistance with determining the time it takes for the masses to travel 60 cm. They highlight that with constant acceleration, the distance covered can be calculated using the appropriate kinematic equation. The conversation emphasizes the relationship between acceleration, distance, and time in this context. The user is looking for the correct formula to proceed with their calculations.
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Homework Statement



An Atwood’s Machine has a solid cylindrical pulley with a mass of 80 g and a radius of 10 cm. A 1.1 kg mass is hung on one side and a 1.05 kg mass on the other side. Find the acceleration of the two masses, and the time for them to travel a distance of 60 cm.

2. The attempt at a solution

I was successful in finding the acceleration of the first part of the question now can someone help me pinpoint a equation to solve the 2nd part?
 
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If you know the acceleration of a body and if the acceleration is constant can you not find the distance covered in t seconds.If u can then put the value of the distance i.e 60 cm in the equation and solve for t.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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