Solving Block on Incline Homework Problem

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SUMMARY

The discussion focuses on solving a physics problem involving a 725 gm block sliding down a 30° inclined plane with an acceleration of 1.5 m/s². Participants analyze the forces acting on the block, specifically the total force exerted by the plane and the force exerted on the plane by the block. Key equations mentioned include Newton's second law (fnet = ma) and the need to consider both horizontal and vertical components of the forces. The correct approach involves converting mass to kilograms and applying vector resolution to find the magnitudes and directions of the forces.

PREREQUISITES
  • Understanding of Newton's second law (fnet = ma)
  • Knowledge of force diagrams and vector resolution
  • Ability to convert units (grams to kilograms)
  • Familiarity with inclined plane physics
NEXT STEPS
  • Learn about vector resolution in two dimensions
  • Study the forces acting on objects on inclined planes
  • Explore the concept of normal force and friction in physics
  • Practice solving problems involving forces and acceleration
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking to clarify concepts related to forces and motion.

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Homework Statement



A 725 gm block slides down an inclined plane that makes an angle of 30° with the horizontal. It accelerates at 1.5 m/s2.

a) Find the magnitude and direction of the total force exerted on the block by the plane. For the direction, give the angle as measured counterclockwise from the vertical (in degrees).

b)What are the magnitude and direction of the force exerted on the plane by the block? For the direction, give the angle as measured counterclockwise from the vertical (in degrees).


I figured out the force of Friction was 2465

Homework Equations


fnet = ma
Not really sure on what other equations to use

The Attempt at a Solution



For a) I tried drawing a fbd and making a a triangle to find the hypotenuse to get the magnitude of the normal force, but I'm not getting it right. I also did sqrt(NormalForce^2 + Friction^2). For b), I'm not sure where to start.

Could you please walk me through this because I'm a bit confused now. Thanks~
Can someone please walk me through this because I'm a bit confused.
 
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I figured out the force of friction was 2465
Probably on the right track, but did you remember to convert the grams to kg?
I don't think you need this force because it is part of the plane on box force you are trying to find.

This is an unusual question! Back to basics, I think.
Sum of the forces on the box = ma.
Gravity force + force of plane on box = ma

It is 2D so you need to work with two perpendicular directions. You could do it with horizontal and vertical directions or go with along the plane and into the plane.
 

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