Solving Boolean Algebra: a'b'c' + abc = 1?

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The equation a'b'c' + abc = 1 is not universally true in Boolean algebra. It holds only when the variables a, b, and c are all equal, either all 0 or all 1. To demonstrate this, constructing a truth table reveals the conditions under which the equation is valid. Alternatively, using the expression (abc)' + abc = 1 shows that it covers all possible values of abc, yielding a consistent result of 1. Thus, the original equation's validity is limited to specific cases.
killerfish
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Hi guys,

I'm new to boolean algebra, i couldn't get this through...

a'b'c' + abc = 1 ? or i have to use (abc)' + abc = 1 to get 1 ?

Thanks you.
 
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(abc)' + abc = 1. There are only 2 possible values for abc, and they are 0 and 1. So it is very obvious that if abc isn't 1, then (abc)' is, and vice versa. So 1 or 0 = 1, 0 or 1 = 1. To prove that a'b'c' + abc = 1 isn't always necessarily true, you can construct a truth table with a b c a' b' c' and your answer. You will find that statement is only true when a,b,c are all the same value.
 
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