Solving Circuit Resistor Equations: Current, Voltage, Power

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Discussion Overview

The discussion revolves around solving a circuit problem involving resistors, specifically finding the current flowing through each resistor, the voltage across each resistor, and the power consumed by each element in the circuit. The context includes homework-related inquiries and mathematical reasoning regarding circuit analysis.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions whether the current is 10 A, noting they obtained two potential answers: 0 A and 10 A.
  • Another participant suggests that the degenerate solution (I=0) is not physical in this context and recommends using I=10 A instead.
  • A participant proposes that adding up the resistor values can help determine the total current flowing, given the supply voltage.
  • There is a request for clarification on the term "degenerate solution," with one participant explaining it as a solution where all terms in the equation equal zero, which may not be meaningful in this scenario.
  • Another participant advises that dividing by I before solving the equation would prevent I=0 from being a degenerate solution.

Areas of Agreement / Disagreement

Participants express differing views on the validity of the degenerate solution, with some arguing that I=0 is not a viable option while others seek clarification on the term and its implications. The discussion remains unresolved regarding the best approach to the problem.

Contextual Notes

There is uncertainty regarding the definitions and implications of degenerate solutions in the context of circuit analysis. Participants have not reached a consensus on how to handle the potential solutions for current.

sonutulsiani
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Homework Statement




Find current flowing through each resister, voltage across each resister and power consumed by each element in the following circuit.

See the attachment


Homework Equations





The Attempt at a Solution



The question I want to ask here is that is the current = 10 A? Because I got 2 answers for current, 0 A and 10 A.

I did this:

I combined 10 and 10 ohm resistors to get a 5 ohm resistor.
Now total power consumed=total power supplied

So I^2(3) + I^2(5) + I^2(2) = 100I
which gives I = 0 or 10. Which one should I take?
 

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sonutulsiani said:

Homework Statement




Find current flowing through each resister, voltage across each resister and power consumed by each element in the following circuit.

See the attachment


Homework Equations





The Attempt at a Solution



The question I want to ask here is that is the current = 10 A? Because I got 2 answers for current, 0 A and 10 A.

I did this:

I combined 10 and 10 ohm resistors to get a 5 ohm resistor.
Now total power consumed=total power supplied

So I^2(3) + I^2(5) + I^2(2) = 100I
which gives I = 0 or 10. Which one should I take?

I=0 is called the degenerate solution, and is not physical in this case. Use I=10.
 


Ok but what is the reason again? What is degenerate solution ?
 


If you add up the resistor values, you can get the total current flowing because you know the supply voltage.

Then take this current and work out the voltage across each resistor and the power dissipated in it.

With this circuit, you can tell by looking at it that zero current is not an option.
 


sonutulsiani said:
Ok but what is the reason again? What is degenerate solution ?

I apologize if I'm using and incorrect term there. I've been googling for a bit trying to find you a good definition, with very little luck so far. By degenerate solution, I meant when the variable x = 0 is a solution to an equation f(x) = 0, and it is a solution because all terms in the equation are zero. It's like multiplying both side of any equation by zero, and saying, yes, both sides are equal now.

In your equation you had I on one side and all I^2 on the other. You should divide by I in that case, before solving the equation. If you do that, you will not end up with I=0 as a degenerate solution of the equation.
 

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