Solving Current: Copper Cylinder Density & Electron Count

Thread starter sbp_387
Start date Jan 30, 2007
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To find the current in the hollow copper cylinder, first calculate the cross-sectional area using the inner diameter. The formula for the area is A = π(d/2)², where d is the inner diameter. Multiply the current density (170,000 A/m²) by the cross-sectional area to determine the total current. The electron density of copper (8.5E28) is relevant for understanding conductivity but not directly needed for this calculation. Properly categorizing such questions in the homework section is advised for better assistance.

Jan 30, 2007

sbp_387

I need help solving a problem
A 60 g hollow copper cylinder is 10 cm long and has an inner diameter of 1.0 cm. The current density along the length of the cylinder is 170,000 A/m^2. What is the current in the cylinder?

the electron density for copper is 8.5E28

thanks for your help

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Jan 30, 2007

ranger

Gold Member

In the future, post questions like this in the homework section.

Any thoughts on how to approach this?

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