Solving Divergent Integral: -infinity Correct?

n.a.s.h
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Homework Statement


I had to solve the integral...After all my work i got -infinity
3
integral sign 1/ [(t-3)^4/3]
1


Homework Equations





The Attempt at a Solution


-infinity...is this correct? and would this be divergent?
 
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The expression

<br /> \frac{1}{(t - 3)^{4/3}}<br />

is complex for t &lt; 3.
 
Yes, it is divergent.
 
It has a real root for t<3, so that's not a problem. I would check how you got the sign on that -\infty, though.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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