Solving Dynamics Problem: Boat Mass m, Velocity v0, Friction Force Fd

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A boat with a mass of 1000 kg is initially moving at 324 m/s and experiences a friction force proportional to its velocity, given by Fd = 70*v. The problem involves determining the time it takes to slow down to 162 m/s, requiring the integration of acceleration, which is not constant. The discussion highlights the need to express acceleration as a function of velocity and time, leading to the formulation of a differential equation. After some trial and error, the correct approach involves applying boundary conditions accurately to solve for time, ultimately revealing that the time to decelerate to the desired speed is approximately 9.9 seconds. The importance of correctly applying initial conditions in integration was emphasized in reaching the final solution.
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Homework Statement



A boat has mass m=1000 kg and is moving at velocity v0=324 ms^-1. Friction force btw the boat and water is proportional to velocity v, Fd=70*v. How long it takes to slow down to 162ms^-1 ?


Homework Equations


I'm not sure which function should I integrate, because acceleration is not constant.


The Attempt at a Solution


I understand Friction force and acceleration as functions of v, but I have no idea how to express these as functions of time, since acc is not constant. Then I would integrate a(t) with respect to time and substitute final velocity for v(t) and from that I'd get the answer.
 
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Draw a force diagram, and apply Newton's 2nd law. You can get the acceleration that way. Then use a = \frac{dv}{dt} to get a differential equation. Solve it and find v in terms of t. Solve for t and substitute correct value of v to find the time.
 
a=-70v/m
∫dv=∫(-70v/m)dt
v=-70/m ∫vdt - the problem is I do not know v in terms of t :(
 
Instead of your second line, do this,
\int{\frac{dv}{v}}=\int{\frac{-70 dt}{m}}
 
I have to correct given informtion v0=25 ms^-1 and v=12.5 ms^-1

Ok, I tried your suggestion and from that I get:

t = (-m*(ln(v) + v0))/70 -what doesn't seem right

After substituting v = 12.5 I get t = 393 s and that is wrong (correct answer should be 9.9s)
 
rammer said:
t = (-m*(ln(v) + v0))/70
This does not agree with my final answer.

Check whether you applied the initial boundary condition (v = v0 when t=0 ) correctly.
 
At t = 0, I'm pretty sure, the integration constant is equal vo (=25).
 
Not ln(vo) ?
 
Yes, you're right, thanks. I finally got it correct. My mistake was I put the constant directly from initial conditions, not solving from integrated function.
 
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