Solving Equation w/ L'Hopital's Rule When x = 0

[Fluidman117]

Homework Statement

I have an equation in which a term equals zero and in this case the whole equations equals zero. I know it is possible to use the L'Hopital's rule to calculate the equation but having I'm having a little trouble.

Homework Equations

The equation I would like to is the following:

k = \frac{pA}{x}*[(\frac{V}{V-Ax})^y - 1]

I have to solve this when x = 0;

The Attempt at a Solution

Plugging in 0 for x, results in 0, which should not be the answer. I figure it is possible to use the l'hospital's rule, but currently only my denominator has the x term which would be approaching zero. But in order to use the rule I would have to manipulate the equation for both the numerator and denominator to approach zero?

 

[vanhees71]

Instead of using de L'Hospital's rule you can (equivalently) expand the expression in the square brackets in powers of x. This should help!

 

[Fluidman117]

But if I would still like to use L'Hopital's rule, how should I proceed?

 

[BvU]

Differentiate the numerator wrt x

Plugging in 0 for x, results in 0

Not true. It results in 0/0 !

 

[Ray Vickson]

But if I would still like to use L'Hopital's rule, how should I proceed?

Your function is $f(x)$ is of the form
f(x) = \frac{N(x)}{x}, \;\; N(x) = pA\left[ \left(\frac{V}{V-Ax}\right)^y -1\right]
When you use l'Hospital's rule (not l'Hopital!) you compute
\lim_{x \to 0} f(x) = \frac{N'(0)}{1},
so all you are really doing is just taking the first term of the series expansion of $N(x)$. l'Hospital and series expansion are really the same thing.