Solving for Alpha in Mechanics: Trig Formulas and Force Components

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CivilSigma
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So I have a mechanics question 2.65 of which I have deduced the following :
[tex]x-Component of all forces[/tex]
[tex]F1 = 150 cos30[/tex]
[tex]F2= 150 cos \alpha[/tex]
[tex]F3 = 150 cos(\alpha+50)[/tex]

[tex]y-Components of all forces[/tex]
[tex]F1 = -150 sin30[/tex]
[tex]F2 = 150 sin \alpha[/tex]
[tex]F3 = 150 cos(50-\alpha)[/tex]

Finally, [tex]R = \sqrt{(\Sigma Fx)^2 + (\Sigma Fy)^2}[/tex]

Now we know the resultant is at max 600 N, how do we go about solving [tex]\alpha[/tex] ? I tried applying various trig formulas like angle addition and subtraction, but I couldn't isolate [tex]\alpha[/tex]. How would you go about solving for alpha?
 
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  • Free-body diagram of bracket A with three forces: 500 N at 30 degrees above the horizontal, 150 N at angle alpha, and 150 N at 50 degrees from it, plus a textbook caption Fig. P2.65.
    Mechanics 1.jpg
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Set R to 600N, then plug everything in and see what you get (and please write it down here, so we can see where exactly you get stuck).