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Phyphy
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I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ?
Phyphy said:I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ?
The equation for a circle passing through (0,1) is x^2 + y^2 = Ae^x, where A is a constant that determines the size of the circle.
To solve for x and y, you can use the substitution method. First, substitute y = 0 into the equation to solve for x. Then, substitute x = 0 into the equation to solve for y. This will give you the x and y coordinates of the point where the circle intersects the x and y axes.
Ae^x represents the radius of the circle passing through (0,1). As x increases, the value of Ae^x also increases, resulting in a larger circle. As x decreases, the value of Ae^x decreases, resulting in a smaller circle.
The value of A directly affects the size of the circle. A larger value of A will result in a larger circle, while a smaller value of A will result in a smaller circle. When A is equal to 0, the circle will collapse into a single point at (0,1).
Yes, the value of A can be negative. This will result in a circle that passes through (0,-1) instead of (0,1). The direction of the circle will also be reversed, with the circle expanding in the negative x direction instead of the positive x direction.