Solving for Average Force: Physics Homework Help for a 0.47 kg Ball

AI Thread Summary
To solve for the average force exerted on a 0.47 kg ball that falls from a height of 34 m and rebounds to 24 m, the impulse concept is crucial. The ball's final velocity upon impact can be calculated using the equation vf = sqrt(2gh), where h is the height fallen. The average force can then be determined by applying the impulse formula, which relates force, time, and change in momentum. The contact time with the ground is given as 1.8 ms, which is essential for calculating the average force. Understanding and applying these physics principles will lead to the correct solution.
bunton33
Messages
1
Reaction score
0

Homework Statement



After falling from rest from a height of 34 m, a 0.47 kg ball rebounds upward, reaching a height of 24 m. If the contact between ball and ground lasted 1.8 ms, what average force was exerted on the ball?


Homework Equations



vf^2=2gh

vf=sqrt 2gh.

force*time=2sqrt(2gh)


The Attempt at a Solution



i have tried to plug in but i cannot seem to get it correct. help please!
 
Physics news on Phys.org
Look up the concept of "impulse" in your textbook or Wikipedia. The impulse formula will make short work of this problem!
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Magnitude of the average force during a collision
Replies
2
Views
7K
The speed which a ball must be thrown to reach 8m.
Replies
12
Views
2K
A ball bounces off a brick wall, Find the average acceleration
Replies
5
Views
5K
Average force between baseball and bat
Replies
3
Views
3K
Average force and angle, collision problem
Replies
23
Views
2K
Retarding impact force when object impacts stationary object
Replies
10
Views
2K
Average force on a baseball when struck by a bat
Replies
2
Views
3K
Momentum and impulse of a football
Replies
2
Views
2K
Solve Impulse Force Problem: 75g Ball Dropped from 2.2m
Replies
8
Views
5K
Find the average force of a golf club on a golf ball
Replies
9
Views
6K

Hot Threads

Recent Insights

Back
Top