Solving for Equal Capacitors in Parallel: Potential of Each

AI Thread Summary
When two equal capacitors are connected in parallel, one charged to potential V and the other discharged, they will share the same potential. The conservation of energy does not apply due to energy loss from resistive wires during the charge transfer. The total charge remains conserved, and the potential across both capacitors can be calculated using the charge and capacitance relationships. The correct potential for each capacitor after connection is derived from the total charge and combined capacitance. Following the proper steps will lead to the accurate solution for the potential of each capacitor.
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Homework Statement


2 capacitors of equal capacitance one charged to potential V, and other completely discharged. when the are connected in parallel what would be the potential of each one of them.

Homework Equations



E=1/2 (C.V^2)

The Attempt at a Solution


as they are connected in parallel potential of each wud be same... now by conservation of energy i got answer V/sqrt(2)
am i right??
 
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vipulsilwal said:

Homework Statement


2 capacitors of equal capacitance one charged to potential V, and other completely discharged. when the are connected in parallel what would be the potential of each one of them.

Homework Equations



E=1/2 (C.V^2)

The Attempt at a Solution


as they are connected in parallel potential of each wud be same... now by conservation of energy i got answer V/sqrt(2)
am i right??
What is the charge, Q, on the charged capacitor (in terms of C and V)?
What is the total charge, Q', on the two capacitors when they are connected together?
What is the capacitance, C', of the two capacitors when connected together (in terms of C)?
What is the potential V' (in terms of Q' and C')?
Now express the answer in terms of C and V.

AM
 
When you connect the two capacitors in parallel, energy will be lost due to the charges moving through the resistive wires. So conservation of energy doesn't apply in this case. But the total number of charges is conserved. So follow Andrew Mason's steps and you will get the right answer.
 
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