Solving for Force Given Rotational Inertia and Mass

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A 0.70-kg disk with a rotational inertia of MR²/2 is suspended from the ceiling, with a 2.0-kg mass hanging from a string wrapped around it. The discussion focuses on calculating the force exerted by the suspension as the mass falls and the disk rotates, with the correct answer identified as approximately 9.77N. Participants clarify the application of Newton's second law and the correct forces acting on the disk, emphasizing the importance of accurately identifying tension and acceleration in the equations. Misunderstandings regarding the free body diagram and the variables used in the equations are addressed, leading to a consensus on the correct approach. Overall, the discussion highlights the significance of proper variable representation and understanding of forces in rotational dynamics.
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A 0.70-kg disk with a rotational inertia given by MR2/2 (M) is free to rotate on a fixed horizontal axis suspended from the ceiling. A string is wrapped around the disk and a 2.0-kg mass (m) hangs from the free end. If the string does not slip, then as the mass falls and the cylinder rotates, the suspension holding the cylinder pulls up on the cylinder with a force of:

A. 6.9N
B. 9.8N
C. 16N
D. 26N
E. 29N
ans: B

My solution:

ma = mg - F
Fr = Ia/r
mg - ma = Ia/r2

mg - ma = Ma/2

a = (mg)/(m + 0.5M)

ƩFy = FN - Mg - Ma

FN = M (g + a) = ~9.77N

Please point out any errors since I really want to ensure I understood every process throughly and correctly. If you have anything to add, in terms of helpful steps or things to consider in general, please reply! :)
 
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You were doing well until here:
MathewsMD said:
ƩFy = FN - Mg - Ma
Look at the free body diagram for the disk (cylinder?).
Where is there an Ma in there?
 
[ignore/]
 
Last edited:
zahbaz said:
"ƩFy = FN - Mg - Ma"

Another way to ask what haruspex is getting at:
What does ƩFy equal? Meaning, do we have acceleration or are the sum of y forces zero?

Sorry, I meant to add ƩFy = 0, isn't that a correct assumption?
 
MathewsMD said:
Sorry, I meant to add ƩFy = 0, isn't that a correct assumption?

Yes, but you don't have the right contributors to ƩFy.
 
Ohh... yeah, that's a totally correct assumption. I misread the scenario!

I got the same answer, 9.77... but not sure where you have the Ma term as haruspex mentioned. If you consider the mass is falling with F = ma, how much tension remains on the line? This is a downwards force on the cylinder.

ƩFy = FN - Mg - tension
 
Okay, thank your for clearing that up. Yes, I used the wrong variable name but calculated it as ma was tension.
 
MathewsMD said:
Okay, thank your for clearing that up. Yes, I used the wrong variable name but calculated it as ma was tension.
OK, so you meant ƩFy = FN - Mg - m(g-a), right?
But in the next line of the OP you wrote M (g + a), which is not so easily explained?
 
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