Solving for k & P0: 5 Decimal Places of Accuracy

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The equations 1150 = P0exp(2k) and 11500 = P0exp(8k) can be used to derive values for k and P0. By dividing the first equation by the second, P0 cancels out, simplifying the problem. This allows for the calculation of k with high precision, aiming for at least five decimal places. After resolving the algebraic issues, accurate values for both k and P0 can be obtained. The key to solving this is recognizing the cancellation of P0 through division.
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From the facts that 1150 = P0exp(2 k) and 11500 = P0exp(8 k) we can solve for k and P0. Provide at least five decimal places of accuracy for k and at least two decimal places of accuracy for P0.

I've got
P0 = 1150/e^2k
and
P0 = 11500/e^8k

but when i try to solve for any variable by substituting I keep ending up cancelling out all the variables
help!

thanks
 
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nvm i had crazy algebra
 
Dividing one equation by the other eliminates P0.
 

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