Solving for Magnetic Flux in a Square Loop

AI Thread Summary
The magnetic flux through a square loop in a magnetic field is calculated using the equation MFlux = BACos(theta). In this case, a 3.0 T magnetic field makes a 55-degree angle with the loop, which is 25 cm on each side. The initial calculation yielded 0.11 Wb, but the angle should be considered with respect to the plane of the coil, requiring the use of MFlux = BAsin(theta). This adjustment indicates that the correct approach is to use the sine function for the angle. The final answer should reflect this correction for accurate results.
louza8
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Homework Statement



A 3.0 magnetic field makes a 55deg angle with a square loop 25cm on a side

Homework Equations



MFlux = BACos(theta)

The Attempt at a Solution



=3*.252*cos(55)
=0.11Wb

Answer is to 2 sigfigs. This is a masteringphysics problem, and I'm wondering if I'm missing something here or if MP has the wrong answer stored.
 
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The relevant equation given by you is for a field making an angle θ with the vertical.

In the problem the angle is with the plane of the coil. So

MFlux = BAsinθ.
 
thanks
 

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