Solving for Minimum Angle for Home Run

AI Thread Summary
To determine the minimum angle for a home run, the projectile's path is modeled using parametric equations based on the initial speed and height of the ball. The distance to the center field fence is 400 feet, and it must clear a height of 10 feet. By substituting the distance into the x-equation and solving for time, the value of t is derived. This time is then substituted into the y-equation to establish a relationship involving theta. The equation can be simplified using trigonometric identities, allowing for the calculation of the minimum angle necessary for the ball to clear the fence.
jazz20
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Homework Statement


the center field fence in a ball park is 10ft high and 400 feet from home plate. the ball is hit 3 ft above ground. it leaves the bat at an angle of theta degrees with the horizontal speed of 147.67ft/second. find the minimum angle at which the ball must leave the bat in order for hit to be a home run.
the path of the projectile is modeled by the parametric equations:
x=v0cos(theta)t
y=3+(v0sin(theta)t-15t^2

Homework Equations





The Attempt at a Solution


substitute 400 in for x and 147.67 for v0to solve for t
t=400/(146.67cos(theta)
then i took t and put it into the equation for y
y=3+(147.67sin(theta)(400/(146.67cos(theta))-16(400/(146.67cos(theta))^2


Did I do this correctly? If so, can some one help me with the math to solve for theta?
 
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jazz20 said:
1.

The Attempt at a Solution


substitute 400 in for x and 147.67 for v0to solve for t
t=400/(146.67cos(theta)
then i took t and put it into the equation for y
y=3+(147.67sin(theta)(400/(146.67cos(theta))-16(400/(146.67cos(theta))^2


You can rewrite the equation as
y = 3 + 400*tanθ - 16*400^2*sec^2θ/146.67^2 [ 1/cosθ = secθ]
Put sec^2θ = 1 + tan^2θ,and solve the quadratic for tanθ.
 
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