Solving for Orthogonal Trajectories

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Homework Help Overview

The problem involves finding the set of orthogonal trajectories for a family of curves defined by the equation (x-c)^2 + y^2 = c^2, which represents circles centered on the x-axis. The original poster is exploring various options provided in a multiple-choice format.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to manipulate the equation and derive a differential equation for the orthogonal trajectories. Some participants suggest visualizing the curves to identify the orthogonal trajectories more intuitively. Others discuss the properties of the original curves, such as their centers and radii.

Discussion Status

Participants are actively engaging with the problem, with some suggesting graphical methods while others focus on algebraic manipulation. There is a recognition of the complexity involved in the algebraic approach, and some participants express uncertainty about graphing the equations. The original poster expresses a belief that they have identified the correct answer, but this is not universally confirmed.

Contextual Notes

There is mention of the original curves being circles and the challenges faced in graphing and algebraic manipulation. The discussion reflects a mix of approaches, with some participants questioning the necessity of graphing while others emphasize its usefulness.

vorse
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Homework Statement



Which of the following is the set of orthogonal trajectories for the family indicated by

(x-c)^2 + y^2 = c^2

a). (x-c)^2 + y^2 = c^2

b). (x-c)^2 - y^2 = c^2

c). x^2 + (y-c)^2 = c^2

d). x^2 - (y-c)^2 = c^2

e). None of the above




Homework Equations



I think this is a homogenous equation after playing with the variables and substituting for C. I came up with:

y' = (y^2 - x^2)/xy

I then substitute y=xv after setting y' = 1/y' for the orthogonal trajectories and tried to solve the equation, but ended up with answers no where close to the choices.



The Attempt at a Solution


 
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Hi vorse! :smile:

Let's do it the easy way :wink:

draw a few curves, and that should show you the most obvious orthogonal trajectory …

which of a) to e) does that one lie on? :smile:
 
I was afraid you'd said I have to graph the equation; I can never make heads to tail of what I draw out.
 
ok … (x-c)2 + y2 = c2 is obviously a circle.

So, for each value of c, what is its centre, what is its radius, and what are the endpoints of its "horizontal" diameter?
 
Ok, I figured out the answer. I think it's answer choice C. It's just my answer has something like 2c as one of the constant, and I guess the answer choice reduce it down to just C. Btw, I didn't graph the equation; it is a homogenous equation and can be solve that way; just the algebra manipulation was confusing. Thanks for all the help PF. Thanks for trying to help me tiny tim.
 
Last edited:
vorse said:
Ok, I figured out the answer. I think it's answer choice C.

Yup! :smile:

But a quick sketch always helps …

in this case, the original curves are the circles with centres on the x-axis, all touching each other (and the y-axis) at the origin.

Quickly hovering over this with a pencil shows that the orthogonal trajectories must approach the y-axis horizontally, and must all go through the origin …

which choice C does, since it's the circles with centres on the y-axis. :wink:

hmm … are those all of the orthogonal trajectories?

(btw, the wiki page http://en.wikipedia.org/wiki/Orthogonal_trajectories" )
 
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