Solving for Orthogonal Trajectories

vorse
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Homework Statement



Which of the following is the set of orthogonal trajectories for the family indicated by

(x-c)^2 + y^2 = c^2

a). (x-c)^2 + y^2 = c^2

b). (x-c)^2 - y^2 = c^2

c). x^2 + (y-c)^2 = c^2

d). x^2 - (y-c)^2 = c^2

e). None of the above




Homework Equations



I think this is a homogenous equation after playing with the variables and substituting for C. I came up with:

y' = (y^2 - x^2)/xy

I then substitute y=xv after setting y' = 1/y' for the orthogonal trajectories and tried to solve the equation, but ended up with answers no where close to the choices.



The Attempt at a Solution


 
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Hi vorse! :smile:

Let's do it the easy way :wink:

draw a few curves, and that should show you the most obvious orthogonal trajectory …

which of a) to e) does that one lie on? :smile:
 
I was afraid you'd said I have to graph the equation; I can never make heads to tail of what I draw out.
 
ok … (x-c)2 + y2 = c2 is obviously a circle.

So, for each value of c, what is its centre, what is its radius, and what are the endpoints of its "horizontal" diameter?
 
Ok, I figured out the answer. I think it's answer choice C. It's just my answer has something like 2c as one of the constant, and I guess the answer choice reduce it down to just C. Btw, I didn't graph the equation; it is a homogenous equation and can be solve that way; just the algebra manipulation was confusing. Thanks for all the help PF. Thanks for trying to help me tiny tim.
 
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vorse said:
Ok, I figured out the answer. I think it's answer choice C.

Yup! :smile:

But a quick sketch always helps …

in this case, the original curves are the circles with centres on the x-axis, all touching each other (and the y-axis) at the origin.

Quickly hovering over this with a pencil shows that the orthogonal trajectories must approach the y-axis horizontally, and must all go through the origin …

which choice C does, since it's the circles with centres on the y-axis. :wink:

hmm … are those all of the orthogonal trajectories?

(btw, the wiki page http://en.wikipedia.org/wiki/Orthogonal_trajectories" )
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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