Solving for q2: Find Charge of Particle 2

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To find the charge of particle 2 (q2), the attractive force of 2.3 N between the two particles must be considered, along with the given charge of particle 1 (q1 = +3.5 µC) and their separation distance of 0.25 m. The correct formula to use is F = k(q1 * q2) / r^2, where k is Coulomb's constant. After rearranging the equation to solve for q2, the calculation yields a magnitude of approximately -4.57 x 10^-12 C, indicating that q2 must be negative to create an attractive force. The sign of q2 is crucial as it determines the nature of the interaction between the two charges.
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Homework Statement



In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?

Homework Equations





The Attempt at a Solution



not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2

should that work? and would the sign be + or -?

thanks.
 
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rcmango said:

Homework Statement



In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?

Homework Equations





The Attempt at a Solution



not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2

should that work? and would the sign be + or -?

thanks.

you want the force to be attractive, as stated in the problem. do like charges attract or repel?
 
like charges repel. however, is my formula equation correct?
 
You are missing a charge, remember

F = k \frac{qQ}{r^2}
 
Okay, I see, so then I solve for Q2, correct?

which shows now 2.3 N = ((8.99 x 10^9) * (2.3) * (Q2) )/ .25^2

i get something like: -4.57 x 10^-12 C
 
You should solve for what you want algebraically before you put in numbers. It is a lot easier that way. So you are right, you want the value of the other charge.

q_2 = \frac{r^2 F}{kq_1}

in terms of the numbers that would be... (you do it)

*note: you made a mistake for the value of the first charge. Also note that I just gave you the magnitude of the charge, you will have to figure out the sign.
 
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