Engineering Solving for R in RLC Circuit to Achieve 3V Magnitude of V

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To find the resistance R that achieves a voltage magnitude of 3 volts in the RLC circuit, a differential equation must be established. The equation should represent the current entering node V from the source and the current leaving node V through the inductor (L) and capacitor (C). Although phasors are not applicable in this case, the problem can be approached by transforming the integro-differential equation into an ordinary differential equation. Solving this equation will yield the necessary value for R. Understanding these concepts is crucial for accurately determining the resistance in the circuit.
bacthiar_ahmed
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In the circuit shown below, find the value of the resistance R that is necessary to make the magnitude of V equal to 3 volts.

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Can anyone please help me to solve this out?
 
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rude man said:
Have you covered phasors?

No phasors is given bro...
 
In that case you have to write a differential equation . Write the diff. eq. for current entering node V from the source = current leaving node V through L and C. This actually starts as an integro-differential equation but you can change it to an ordinary diff. eq.
 

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