Solving for Rotational Velocity of a Ring and Bug System | Homework Question

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The discussion revolves around a physics homework problem involving a ring and a bug walking on it, focusing on calculating the ring's rotational velocity as the bug moves. The user attempts to apply conservation of momentum and angular momentum but encounters discrepancies with the book's answers. Key equations are derived, but the user is unsure about the interpretation of the pivot point at the rim of the ring. Clarification on the pivot's meaning and its implications for the problem is sought. The thread highlights the complexities of applying conservation laws in rotational dynamics.
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1. Homework Statement

A ring of mass M and radius R lies on its side on a frictionless table. It is pivoted to the table at its rim. A bug of mass m walks around the ring with speed v, starting at the pivot. What is the rotational velocity of the ring when the bug (a) is halfway around and (b) back at the pivot?

2. Homework Equations

p=mv

3. The Attempt at a Solution

If I assume that only momentum and angular momentum are conserved, and that the bug still has speed v with respect to the ring, I get these equations:

-mv = m(v + V) + Mv
-mRv = -mR(v + V) + M(R^2)(omega)

where V is the velocity of the ring and omega is the angular velocity. I solve these equations for omega, and I don't get the answer in the book.

Where did I go wrong? Thanks in advance for all your help.
 

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"It is pivoted to the table at its rim."

What does this mean?
 
LawrenceC said:
"It is pivoted to the table at its rim."

What does this mean?

It is in attached picture
 
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