In summary: I can't figure out the velocity of the boy as he leaves the slide without it, how would I go about figuring it outHave you given all the information ?In summary, a water slide is frictionless and begins at rest at the top of the slide. A 50 kg boy is observed to hit the water 7 meters from the end of the slide, as shown.
#36
hannsparks
32
0
would it make sense to solve for vi using the conservation of energy equation?
I thought you had already worked out another velocity.
Ok, forget my earlier post about vi being a vertical velocity - that's wrong.
the 10 m/s, that is the horizontal velocity that the boy has when he leaves the slide. I think you called that Vb.
Ok, now we have to find the vertical velocity that the boy hits the water with.
He falls from a height h = 2.4 m ( the height of the slide above the water). He falls with a acceleration of g = 9.8 m/s². So,
v² - u² = 2as (with u,v,a,s as defined before)
v² - 0 = 2g*2.4
v = 6.858 m/s
===========
Then,
v² + Vb² = speed²
#38
hannsparks
32
0
wow! thanks fermat for all your patience with me I greatly appreciate it! I only discovered this website two days ago and I thank God I did you've been a tremendous help. thanks again